Calculation of the weight of submerged objects (Archimedes’ principle)

Understanding the Calculation of the Weight of Submerged Objects Using Archimedes’ Principle

Calculating the weight of submerged objects is essential in fluid mechanics and engineering. This process uses Archimedes’ principle to determine buoyant forces and effective weight.

This article explores detailed formulas, common values, and real-world applications for precise weight calculations underwater. Expect comprehensive tables, explanations, and examples.

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  • Calculate the apparent weight of a steel block submerged in freshwater.
  • Determine the buoyant force on a wooden log floating in seawater.
  • Find the volume of a submerged object given its weight and fluid density.
  • Compute the weight loss of an object submerged in oil with known density.

Comprehensive Tables of Common Values for Submerged Weight Calculations

To accurately calculate the weight of submerged objects, it is crucial to understand the typical values of physical properties involved. The following tables provide extensive data on fluid densities, gravitational acceleration, and material densities commonly used in Archimedes’ principle calculations.

FluidDensity (kg/m³)Typical Temperature (°C)Notes
Freshwater998.220Standard freshwater density at room temperature
Seawater102520Average ocean water density
Mercury1354620High-density liquid metal
Olive Oil92020Common vegetable oil density
Air (at sea level)1.22515Density of air at standard conditions
Alcohol (Ethanol)78920Common organic solvent
Glycerin126020Viscous liquid used in various applications
MaterialDensity (kg/m³)Typical UseNotes
Steel7850Construction, machineryCommon structural metal
Aluminum2700Aerospace, packagingLightweight metal
Wood (Oak)710Furniture, constructionHardwood with moderate density
Concrete2400Building materialComposite material
Plastic (Polyethylene)950Packaging, containersCommon polymer
Glass2500Windows, containersBrittle, transparent material
Physical ConstantSymbolValueUnitsNotes
Acceleration due to gravityg9.80665m/s²Standard gravity at Earth’s surface
Atmospheric pressure (sea level)P₀101325PaStandard atmospheric pressure
Water temperature effect on densityρ variation±5%kg/m³Density varies with temperature

Fundamental Formulas for Calculating the Weight of Submerged Objects

Archimedes’ principle states that a body submerged in a fluid experiences an upward buoyant force equal to the weight of the fluid displaced by the body. This principle forms the basis for calculating the apparent weight of submerged objects.

Below are the essential formulas, each explained in detail with variable definitions and typical values.

1. Buoyant Force (Fb)

The buoyant force exerted on a submerged object is given by:

Fb = ρfluid × Vdisplaced × g
  • Fb: Buoyant force (Newtons, N)
  • ρfluid: Density of the fluid (kg/m³)
  • Vdisplaced: Volume of fluid displaced by the object (m³)
  • g: Acceleration due to gravity (9.80665 m/s²)

The buoyant force depends directly on the fluid density and the volume of fluid displaced. For fully submerged objects, Vdisplaced equals the volume of the object.

2. Weight of the Object in Air (Wair)

The weight of the object in air is calculated as:

Wair = m × g = ρobject × Vobject × g
  • Wair: Weight of the object in air (N)
  • m: Mass of the object (kg)
  • ρobject: Density of the object (kg/m³)
  • Vobject: Volume of the object (m³)
  • g: Acceleration due to gravity (9.80665 m/s²)

This formula assumes the object is weighed in air, where buoyant forces from air are negligible for most practical purposes.

3. Apparent Weight of the Object When Submerged (Wsubmerged)

The apparent weight is the effective weight of the object when submerged, accounting for the buoyant force:

Wsubmerged = Wair − Fb = (ρobject − ρfluid) × Vobject × g
  • Wsubmerged: Apparent weight underwater (N)
  • Other variables as defined above

This formula is critical for determining how heavy an object feels underwater, which is essential in marine engineering, diving, and fluid dynamics.

4. Volume of the Object from Weight and Density

If the weight and density of the object are known, the volume can be calculated as:

Vobject = m / ρobject = Wair / (ρobject × g)
  • Vobject: Volume of the object (m³)
  • m: Mass of the object (kg)
  • Other variables as defined above

5. Density of the Object from Weight and Volume

Conversely, if the weight and volume are known, the density is:

ρobject = m / Vobject = Wair / (Vobject × g)
  • ρobject: Density of the object (kg/m³)
  • Other variables as defined above

6. Buoyant Force for Partially Submerged Objects

For objects floating or partially submerged, the buoyant force equals the weight of the displaced fluid volume:

Fb = ρfluid × Vdisplaced × g

Here, Vdisplaced is less than the total volume of the object, and equilibrium is reached when:

Wair = Fb

This condition is fundamental in ship design and buoyancy control.

Detailed Real-World Examples of Submerged Weight Calculations

Applying Archimedes’ principle in practical scenarios requires careful consideration of fluid properties, object geometry, and environmental conditions. Below are two detailed examples illustrating these calculations.

Example 1: Calculating the Apparent Weight of a Steel Block Submerged in Freshwater

A steel block with a volume of 0.05 m³ is fully submerged in freshwater at 20°C. Calculate the apparent weight of the block underwater.

  • Given:
    • Volume, Vobject = 0.05 m³
    • Density of steel, ρobject = 7850 kg/m³
    • Density of freshwater, ρfluid = 998.2 kg/m³
    • Acceleration due to gravity, g = 9.80665 m/s²

Step 1: Calculate the weight of the steel block in air:

Wair = ρobject × Vobject × g = 7850 × 0.05 × 9.80665 = 3847.6 N

Step 2: Calculate the buoyant force exerted by freshwater:

Fb = ρfluid × Vobject × g = 998.2 × 0.05 × 9.80665 = 489.3 N

Step 3: Calculate the apparent weight underwater:

Wsubmerged = Wair − Fb = 3847.6 − 489.3 = 3358.3 N

The steel block effectively weighs 3358.3 N underwater, significantly less than its weight in air due to buoyancy.

Example 2: Determining the Volume of a Wooden Log Floating in Seawater

A wooden log weighs 700 N in air and floats partially submerged in seawater with a density of 1025 kg/m³. Calculate the volume of the log and the submerged volume when floating.

  • Given:
    • Weight in air, Wair = 700 N
    • Density of seawater, ρfluid = 1025 kg/m³
    • Density of oak wood, ρobject = 710 kg/m³
    • Acceleration due to gravity, g = 9.80665 m/s²

Step 1: Calculate the volume of the log:

Vobject = Wair / (ρobject × g) = 700 / (710 × 9.80665) ≈ 0.1003 m³

Step 2: Calculate the submerged volume when floating:

At equilibrium, the buoyant force equals the weight:

Fb = ρfluid × Vsubmerged × g = Wair

Rearranged to find submerged volume:

Vsubmerged = Wair / (ρfluid × g) = 700 / (1025 × 9.80665) ≈ 0.0696 m³

Step 3: Calculate the fraction of the log submerged:

Fraction submerged = Vsubmerged / Vobject = 0.0696 / 0.1003 ≈ 0.694

Approximately 69.4% of the log’s volume is submerged when floating in seawater.

Additional Considerations and Advanced Topics

While the above formulas and examples cover fundamental calculations, several factors can influence the accuracy and applicability of submerged weight calculations in real-world scenarios.

  • Temperature and Pressure Effects: Fluid density varies with temperature and pressure, especially in deep-sea environments. Accurate calculations require temperature and pressure corrections using fluid property tables or equations of state.
  • Compressibility of Fluids and Objects: At high pressures, both fluids and materials may compress, altering volume and density. This is critical in submarine and deep-ocean engineering.
  • Surface Tension and Viscosity: For small objects or those near fluid interfaces, surface tension and viscous forces may affect buoyancy and apparent weight.
  • Non-Uniform Density Distributions: Objects with varying density or hollow structures require integration of buoyant forces over their volume.
  • Dynamic Effects: Movement through fluid introduces drag and dynamic pressure changes, complicating static buoyancy calculations.

Authoritative Resources for Further Study

Summary of Key Points

  • Archimedes’ principle provides the foundation for calculating the apparent weight of submerged objects by relating buoyant force to displaced fluid weight.
  • Accurate calculations require knowledge of fluid and object densities, volume, and gravitational acceleration.
  • Common formulas include buoyant force, weight in air, apparent submerged weight, and volume or density derivations.
  • Real-world applications span marine engineering, material science, and fluid dynamics, with examples illustrating practical use.
  • Environmental factors and advanced physical effects may necessitate corrections for precise engineering calculations.

Mastering these principles enables engineers and scientists to design safer vessels, optimize material usage, and understand fluid-object interactions in diverse environments.