Calculation of Thermal Efficiency of Chemical Processes

Understanding Thermal Efficiency in Chemical Processes: A Critical Metric

Thermal efficiency calculation quantifies energy utilization in chemical reactions and processes. It measures how effectively thermal energy converts into useful work or products.

This article explores detailed formulas, common values, and real-world applications for calculating thermal efficiency in chemical engineering. Readers will gain expert insights into optimizing process energy use.

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  • Calculate thermal efficiency for an exothermic reaction in a batch reactor.
  • Determine thermal efficiency of a steam reforming process with given feed conditions.
  • Evaluate thermal efficiency for a catalytic cracking unit using process heat data.
  • Analyze thermal efficiency improvement by heat integration in a chemical plant.

Comprehensive Tables of Common Parameters in Thermal Efficiency Calculations

ParameterSymbolTypical UnitsCommon Value RangeDescription
Heat InputQinkJ, kW·h103 – 107 kJTotal thermal energy supplied to the process
Useful Heat OutputQusefulkJ, kW·h103 – 107 kJEnergy effectively used for chemical conversion or work
Work OutputWoutkJ, kW·h102 – 106 kJMechanical or electrical work derived from the process
Heat LossQlosskJ, kW·h102 – 106 kJEnergy lost to surroundings or inefficiencies
Enthalpy Change of ReactionΔHrxnkJ/mol-500 to +500 kJ/molHeat absorbed or released per mole of reactant
Mass Flow Ratekg/s0.01 – 1000 kg/sMass of reactants or products per unit time
Specific Heat CapacitycpkJ/kg·K0.1 – 5 kJ/kg·KHeat required to raise temperature of unit mass by 1 K
Temperature DifferenceΔTK10 – 1000 KTemperature change during the process
Thermal EfficiencyηthDimensionless (0–1 or %)0.3 – 0.95Ratio of useful energy output to energy input

Fundamental Formulas for Calculating Thermal Efficiency in Chemical Processes

Thermal efficiency (ηth) is a dimensionless measure expressing the effectiveness of converting thermal energy into useful output. The general formula is:

ηth = Quseful / Qin

Where:

  • Quseful = Useful heat or work output (kJ)
  • Qin = Total heat input to the process (kJ)

In chemical processes, useful output can be heat absorbed by the reaction, mechanical work, or heat recovered. For processes involving work output, thermal efficiency can also be expressed as:

ηth = Wout / Qin

Where Wout is the work output (kJ). This is common in power-generating chemical plants.

Calculating Heat Input (Qin)

Heat input is often calculated from fuel combustion or external heating sources:

Qin = ṁfuel × LHV
  • fuel: Mass flow rate of fuel (kg/s)
  • LHV: Lower heating value of fuel (kJ/kg)

Heat Absorbed by Reaction (Qrxn)

For endothermic or exothermic reactions, the heat absorbed or released is:

Qrxn = n × ΔHrxn
  • n: Number of moles reacted (mol)
  • ΔHrxn: Enthalpy change per mole (kJ/mol)

Heat Losses (Qloss)

Heat losses reduce thermal efficiency and include conduction, convection, and radiation losses:

Qloss = Qin – Quseful

Minimizing Qloss is critical for improving ηth.

Thermal Efficiency in Heat Exchanger Integration

When heat integration is applied, thermal efficiency can be expressed as:

ηth = (Qrecovered + Quseful) / Qin
  • Qrecovered: Heat recovered from waste streams (kJ)

Detailed Explanation of Variables and Typical Values

  • Qin: Depends on fuel type and flow rate. For natural gas, LHV ≈ 50,000 kJ/kg.
  • Quseful: Varies with process design; often 60–90% of Qin in optimized plants.
  • Wout: Mechanical work output, e.g., turbine power, typically 30–50% of Qin.
  • ΔHrxn: Reaction enthalpy from thermodynamic tables; exothermic reactions have negative ΔH.
  • : Mass flow rates depend on plant scale; pilot plants may have 0.1–10 kg/s, industrial plants 100–1000 kg/s.
  • cp: Specific heat capacity varies by substance; water ≈ 4.18 kJ/kg·K, gases typically 1–1.5 kJ/kg·K.
  • ΔT: Temperature differences in heat exchangers or reactors range from 50 K to 500 K.

Real-World Applications: Case Studies in Thermal Efficiency Calculation

Case Study 1: Thermal Efficiency of a Steam Methane Reforming Reactor

Steam methane reforming (SMR) is a key industrial process producing hydrogen. It involves the endothermic reaction:

CH4 + H2O → CO + 3H2 (ΔHrxn ≈ +206 kJ/mol)

Given Data:

  • Natural gas feed: 100 kmol/h CH4
  • Steam feed: 300 kmol/h H2O
  • Fuel input (natural gas): 5,000,000 kJ/h
  • Heat loss estimated: 500,000 kJ/h
  • Heat recovered in waste heat boiler: 1,000,000 kJ/h

Step 1: Calculate heat required by reaction

Qrxn = n × ΔHrxn = 100 kmol/h × 206 kJ/mol = 20,600,000 kJ/h

Note: 1 kmol = 1000 mol, so convert accordingly:

Qrxn = 100,000 mol/h × 206 kJ/mol = 20,600,000 kJ/h

Step 2: Calculate useful heat output

Useful heat includes heat absorbed by reaction plus heat recovered:

Quseful = Qrxn + Qrecovered = 20,600,000 + 1,000,000 = 21,600,000 kJ/h

Step 3: Calculate thermal efficiency

ηth = Quseful / Qin = 21,600,000 / 5,000,000 = 4.32 (or 432%)

This value > 1 indicates that the heat input from fuel alone is insufficient to supply the reaction heat, implying external heat or energy sources are involved or data inconsistency. Typically, the fuel input should be higher or the reaction heat lower. This highlights the importance of accurate data and energy balances.

Step 4: Adjusting for heat loss

Subtract heat loss from fuel input:

Qnet_in = Qin – Qloss = 5,000,000 – 500,000 = 4,500,000 kJ/h

Recalculate efficiency:

ηth = 21,600,000 / 4,500,000 = 4.8 (480%)

Again, this suggests the need to verify input data or consider additional heat sources such as electrical heating or exothermic side reactions.

Case Study 2: Thermal Efficiency of a Catalytic Cracking Unit

Catalytic cracking converts heavy hydrocarbons into lighter products. The process is exothermic, releasing heat that can be recovered.

Given Data:

  • Feedstock flow: 50,000 kg/h
  • Heat input from fuel: 10,000,000 kJ/h
  • Heat recovered: 3,000,000 kJ/h
  • Heat loss: 1,500,000 kJ/h
  • Work output (electricity generation): 500,000 kJ/h

Step 1: Calculate total useful energy output

Quseful = Qrecovered + Wout = 3,000,000 + 500,000 = 3,500,000 kJ/h

Step 2: Calculate thermal efficiency

ηth = Quseful / Qin = 3,500,000 / 10,000,000 = 0.35 (35%)

This indicates 35% of the heat input is converted into useful energy, with the rest lost or unutilized.

Step 3: Analyze improvement potential

  • Reducing heat loss by better insulation could increase ηth.
  • Increasing heat recovery systems can improve overall energy utilization.
  • Optimizing catalyst activity may reduce fuel consumption.

Advanced Considerations and Optimization Strategies

Thermal efficiency is influenced by multiple factors including reaction thermodynamics, heat transfer limitations, and equipment design. Advanced methods to improve efficiency include:

  • Heat Integration: Using pinch analysis to optimize heat exchanger networks reduces external heating needs.
  • Process Intensification: Combining reaction and separation steps to minimize energy consumption.
  • Use of Renewable Energy: Incorporating solar thermal or waste heat to supplement fuel input.
  • Advanced Insulation: Minimizing heat losses through improved materials and design.
  • Real-Time Monitoring: Using sensors and control systems to optimize operating conditions dynamically.

Understanding and accurately calculating thermal efficiency enables engineers to benchmark process performance and identify energy-saving opportunities.

Additional Resources and References