Calculation of atmospheric pressure

Understanding the Calculation of Atmospheric Pressure: A Comprehensive Technical Guide

Atmospheric pressure calculation quantifies the force exerted by air above a surface. It is essential for meteorology, aviation, and engineering.

This article explores formulas, variables, tables, and real-world applications for precise atmospheric pressure determination.

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  • Calculate atmospheric pressure at 1500 meters altitude using the barometric formula.
  • Determine pressure at sea level given temperature and altitude.
  • Compute atmospheric pressure changes during a weather front passage.
  • Estimate pressure inside a sealed container at different altitudes.

Extensive Tables of Common Atmospheric Pressure Values

Atmospheric pressure varies with altitude, temperature, and humidity. The following tables provide standard atmospheric pressure values at various altitudes under International Standard Atmosphere (ISA) conditions.

Altitude (m)Altitude (ft)Pressure (Pa)Pressure (hPa / mbar)Pressure (atm)Pressure (mmHg)Temperature (°C)
001013251013.251.00076015
500164095461954.610.94271611.75
1000328189875898.750.8876748.5
1500492184559845.590.8346355.25
2000656279500795.000.7855992
2500820274685746.850.737563-1.25
3000984370112701.120.692528-4.5
40001312361860618.600.610466-10.0
50001640454019540.190.533407-15.5
60001968546600466.000.460351-21.0
70002296639597395.970.391298-26.5
80002624732999329.990.326248-32.0
90002952826799267.990.265201-37.5
100003280822632226.320.223170-43.0

These values are based on the ISA model, which assumes a temperature lapse rate of -6.5 °C/km up to 11 km altitude, a sea level temperature of 15 °C, and a sea level pressure of 101325 Pa.

Fundamental Formulas for Atmospheric Pressure Calculation

Atmospheric pressure calculation relies on physical laws describing how pressure changes with altitude, temperature, and gas properties. The most widely used formulas include the barometric formula, hydrostatic equation, and ideal gas law.

1. Hydrostatic Equation

The hydrostatic equation relates the change in pressure with altitude due to the weight of the air column:

Pressure gradient:
dP/dz = -ρg
  • dP/dz: Rate of change of pressure with altitude (Pa/m)
  • ρ: Air density (kg/m³)
  • g: Acceleration due to gravity (ā‰ˆ9.80665 m/s²)
  • z: Altitude (m)

This differential equation states that pressure decreases with altitude due to the weight of the air above.

2. Ideal Gas Law

To relate air density to pressure and temperature, the ideal gas law is used:

P = ρ R T / M
  • P: Pressure (Pa)
  • ρ: Air density (kg/m³)
  • R: Universal gas constant (8.314462618 J/(molĀ·K))
  • T: Absolute temperature (K)
  • M: Molar mass of air (ā‰ˆ0.0289644 kg/mol)

Rearranged to express density:

ρ = (P M) / (R T)

3. Barometric Formula (Isothermal Atmosphere)

Assuming constant temperature, integrating the hydrostatic equation yields:

P = Pā‚€ Ā· exp(- (M g (z – zā‚€)) / (R T))
  • Pā‚€: Pressure at reference altitude zā‚€ (Pa)
  • z: Altitude where pressure is calculated (m)
  • zā‚€: Reference altitude (m)
  • Other variables: as defined above

This formula is accurate for small altitude ranges where temperature variation is negligible.

4. Barometric Formula with Temperature Lapse Rate (Non-Isothermal Atmosphere)

For altitudes within the troposphere where temperature decreases linearly with altitude, the formula becomes:


P = Pā‚€ Ā· [1 – (L (z – zā‚€)) / Tā‚€](g M) / (R L)
  • L: Temperature lapse rate (K/m), typically 0.0065 K/m
  • Tā‚€: Temperature at reference altitude zā‚€ (K)
  • Other variables: as defined above

This formula is the standard for calculating atmospheric pressure up to approximately 11 km altitude.

5. Conversion Between Pressure Units

Common pressure units and their conversions:

  • 1 atm = 101325 Pa = 1013.25 hPa = 760 mmHg
  • 1 hPa = 100 Pa
  • 1 mmHg ā‰ˆ 133.322 Pa

Detailed Explanation of Variables and Typical Values

  • Pressure (P, Pā‚€): Measured in Pascals (Pa), standard sea level pressure is 101325 Pa.
  • Altitude (z, zā‚€): Height above sea level in meters (m). Reference altitude zā‚€ is often sea level (0 m).
  • Temperature (T, Tā‚€): Absolute temperature in Kelvin (K). Standard sea level temperature is 288.15 K (15 °C).
  • Temperature lapse rate (L): Rate of temperature decrease with altitude, typically 0.0065 K/m in the troposphere.
  • Molar mass of air (M): Average molar mass of dry air is 0.0289644 kg/mol.
  • Universal gas constant (R): 8.314462618 J/(molĀ·K).
  • Gravity (g): Standard acceleration due to gravity, 9.80665 m/s².

Real-World Applications and Case Studies

Case 1: Calculating Atmospheric Pressure at 1500 m Altitude

Given:

  • Altitude z = 1500 m
  • Sea level pressure Pā‚€ = 101325 Pa
  • Sea level temperature Tā‚€ = 288.15 K (15 °C)
  • Temperature lapse rate L = 0.0065 K/m
  • Molar mass M = 0.0289644 kg/mol
  • Gas constant R = 8.314462618 J/(molĀ·K)
  • Gravity g = 9.80665 m/s²

Step 1: Calculate temperature at altitude:

T = Tā‚€ – L Ā· (z – zā‚€) = 288.15 – 0.0065 Ɨ 1500 = 288.15 – 9.75 = 278.4 K

Step 2: Calculate pressure using barometric formula with lapse rate:

Exponent = (g M) / (R L) = (9.80665 Ɨ 0.0289644) / (8.314462618 Ɨ 0.0065) ā‰ˆ 5.25588
P = Pā‚€ Ɨ [1 – (L (z – zā‚€)) / Tā‚€]Exponent = 101325 Ɨ [1 – (0.0065 Ɨ 1500) / 288.15]5.25588
P = 101325 Ɨ (1 – 0.03387)5.25588 = 101325 Ɨ (0.96613)5.25588 ā‰ˆ 101325 Ɨ 0.843 = 85475 Pa

Result: Atmospheric pressure at 1500 m altitude is approximately 85475 Pa (or 854.75 hPa).

Case 2: Estimating Pressure Change During a Weather Front

Scenario: A weather front causes a pressure drop from 1013 hPa to 995 hPa at sea level over 6 hours. Calculate the average rate of pressure change per hour and its impact on altitude pressure.

Step 1: Calculate pressure change:

Ī”P = 995 hPa – 1013 hPa = -18 hPa

Step 2: Calculate average rate of change per hour:

Rate = ΔP / Δt = -18 hPa / 6 h = -3 hPa/h

Step 3: Estimate pressure at 1000 m altitude before and after the front using the barometric formula (assuming constant temperature):

  • Before front: Pā‚€ = 1013 hPa
  • After front: Pā‚€ = 995 hPa
  • Altitude z = 1000 m
  • Temperature T = 288.15 K

Using the isothermal barometric formula:

P = Pā‚€ Ɨ exp(- (M g z) / (R T))

Calculate exponent:

Exponent = (M g z) / (R T) = (0.0289644 Ɨ 9.80665 Ɨ 1000) / (8.314462618 Ɨ 288.15) ā‰ˆ 1.19

Calculate pressure before front:

P_before = 1013 Ɨ exp(-1.19) = 1013 Ɨ 0.304 = 308 hPa

Calculate pressure after front:

P_after = 995 Ɨ exp(-1.19) = 995 Ɨ 0.304 = 302 hPa

Result: Pressure at 1000 m altitude drops by approximately 6 hPa due to the front, consistent with sea level changes.

Additional Considerations and Advanced Topics

While the barometric formulas provide accurate estimates under standard conditions, real atmospheric pressure calculations must consider:

  • Humidity: Water vapor reduces air density, affecting pressure calculations. The virtual temperature correction accounts for this.
  • Non-standard temperature profiles: Temperature inversions or variable lapse rates require piecewise integration or numerical methods.
  • Gravity variation: Gravity slightly varies with latitude and altitude, influencing pressure gradients.
  • Altitude reference systems: Geopotential altitude is often used instead of geometric altitude for more precise calculations.

For precise meteorological or aerospace applications, numerical weather prediction models and radiosonde data are integrated to refine atmospheric pressure estimations.

Useful External Resources for Further Study